許多人應該被債務或金錢上的問題壓得喘不過氣
往往走上不好的方向高利貸之類的..
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有關代書貸款手續費cos sin tan 既問題
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圖片參考:http://imgcld.yimg.com/8/n/AB04762815/o/701103180125613873391740.jpg 圖中..是由一條10m的鐵線所組成的等腰三角形... 大家幫幫手-0-
最佳解答:
Draw a perpendicular bisector(垂直平分線) AD such that BD = DC and AD is perpendicular to BC. D is a point on the line BC. Let AB = AC = x AB + AC + BC = 10 m x + x + BC = 10 BC = 10 – 2x BD = ? BC = ? (10 – 2z) = 5 –x Sine angle ABD = sin 30o = AD/AB AD = AB sin 30o AD = x sin 30o = x (0.5) = ? x Consider triangle ABD (right angle triangle) AB^2 = BD^2 + AD^2 (Pythagorean theorem)畢達哥拉斯定理 x^2 = (5 –x)^2 + (? x)^2 x^2 = 25 –10x + x^2 + 1/4 x^2 1/4 x^2 – 10x + 25 = 0 x^2 – 40x + 100 = 0 Using Quadratic formula,(二次方程式) x = [-b+-(b^2 - 4ac)^0.5]/2 x = {-(-40)+-[(-40)^2 - 4(100)]^0.5}/2 x = {40+-[1200]^0.5}/2 x = {40+-34.641}/2 x =37.32 or 2.6795 Drop 37.32 x = 2.6795 m BC = 10 – 2(2.6795 m) = 4.641 m For triangle ABC AB = 2.6795 m, AC = 2.6795 m, BC = 4.641 m (accurate up to 4 decimal place) angle A = 120o, angle B = angle C = 30o
其他解答:台新銀行信用卡和信貸整合
cos, tan and sin are used in a right-angled triangle
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